starting with the easiest:

there's a pond with lily pads on it. every day, the number of lily pads doubles. on the 40th day, the pond is completely covered. on which day is the pond half covered?

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568146)

if some of those pads are pushing over the banks onto the shore because it's crowded, then it likely became 1/2 full some time during day 38.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22599038)

5

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568170)

10

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568198)

what is the sum of all numbers from 1-99? no calculator/outside aids allowed. also describe how you would do the calculation

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568179)

2 + 98 = 100.

and so on. so we end up with 49 pairs with a value of 100 each. 49 x 100 = 4900. We have 1 50 left over. 4950.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568200)

to find the sum of consecutive intgers, the formula is simple (i believe it was discovered by gauss). add the first and last integers in the sequence and then multiply that by half of the total numbers in the sequence. so here, it's 1+99=100. and then 100*49.5=4950

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568226)

I sample the sum of the first eleven numbers in the series: 1+2+3+4+5+6+7+8+9+10+11 = 66.

From this sample, I can reasonably estimate that each sample of eleven numbers in the overall series sums up to 66, and the total number of samples of eleven numbers is 99/11 = 9. therefore the total sum for 9 samples would be 66*9 = 594 +/- 7.4 at 95% confidence

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568365)

The question is equivalent to asking what is the total area of the blocks either entirely to the left of the line or cut by the line.

(99 x 99)/2 gives you the area to the left of the line but then you have to account for an extra 99 half-blocks for those blocks cut by the line, so:

(99 x 99)/2 + (99 x 0.5) = 4950

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22576162)

edit:

oh, i see why this is confusing everyone. ABC is a 3 digit number, not A*B*C

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568310)

CBA=318

BBCB=1131

pretty simple once you realize that B has to be 1. if you are adding 2 3-digit numbers, the largest possible sum is 1998 (999+999). so B must be 1. C+A must equal 1, so the possible combinations are like 7, 4 or 8, 3, etc. i plugged in 8, 3 first and got the right answer.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568311)

how would you obtain the sum of all results of a set of 1-10 multiplication tables?

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568286)

each row is n*(first row) where n is the value of the row digit

so 55 + 2*55 + ... + 10*55

iow, (1+2+...+10)*55 = 55^2

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568303)

sum(j*sum(i,i=1..10),j=1..10)

sum(j*55,j=1..10)

55*sum(j,j=1..10)

55*55

3025

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568531)

>sample questions for intro level business analyst type job (not quant but you have to have an intuitive grasp of numbers)

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568333)

Before you play, you must pay a fee to enter this game. The question is, what's the maximum amount you're willing to pay in order to play this game?

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568387)

http://en.wikipedia.org/wiki/St._Petersburg_paradox

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568442)

You have a lamp that you need to set on a timer. You want it to come on for two periods daily: 5-8am and 5-8pm. You have an unlimited number of light timers that each can allow power to the lamp for one period (think: those cheap Ikea timers that would allow the light to be on for one period per day). You can run these timers in sequence.

How many of these timers would the lamp require, and each set to what period, so that it will be on for these two time periods during the day?

edit: 24 hour timers. Lamp has one cord going to a single outlet. Multiple timers would run in sequence.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568397)

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568413)

Editing the OP.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568445)

it's either 2 or 3 with the stuff you've specified but i dont understand the rules w/r/t timers.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568466)

2 timers

5am to 8pm

5pm to 8am

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568725)

One hundred ants are dropped on a meter stick. Each ant is traveling either to the left or the right with constant speed 1 meter per minute. When two ants meet, they bounce off each other and reverse direction. When an ant reaches an end of the stick, it falls off.

At some point all the ants will have fallen off. The time at which this happens will depend on the initial configuration of the ants.

Question: over ALL possible initial configurations, what is the longest amount of time that you would need to wait to guarantee that the stick has no more ants?

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568436)

your solution is not rigorous

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568555)

You tell her that you want only a male, and she telephones the fellow who's giving them a bath.

"Is at least one a male?" she asks him. "Yes!" she informs you with a smile.

What is the probability that both beagles are male?

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568507)

MF, FM, MM

in 1/3, both are male

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568542)

MF

MM

where the second spot represents "the other dog."

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568560)

your reasoning is correct for the question "is dog A male" but not for the question "is at least one of dog A or dog B male"

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568582)

Let's phrase the question another way -- you are going to a wedding, and at least one of the people getting married is male. Assuming homos and heteros are equally distributed, what is the probability of the couple being gay? The answer is 50%. There's no left and right, A and B, 1 and 2 slot, etc., you just have a man, and he is either marrying a man or a woman. 50%.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568735)

Mgroom Mbride

Mgroom Fbride

Fgroom Fbride

Fgroom Mbride (lol)

You've eliminated the FF wedding, but you have a 1/3 shot at dat MM

edit: If you know in advance that it is 1 man marrying either a man or a woman, then you are right. But if you are going in blind and ask someone "is atleast 1 partner a man", then the odds play out as I showed above.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568794)

Aboy Bgirl

Aboy Bboy

Agirl Bgirl

Agirl Bboy

The phone call eliminates one outcome (Agirl, Bgirl)

Of the remaining possible outcomes, 1/3 is Boy-Boy

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568567)

It's similar to the monty hall problem, where the fact that the host knows that he is showing you a losing door changes the odds vs if he were to show you a door at random and it happens to be a loser.

If he had only looked at one dog, and it happened to be a male, your numbers are correct.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568762)

The guy on the phone is effectively saying "I have two puppies here, one to my right and one to my left, and at least one of them (the one I'm looking at) is male"

There are four possibilities now:

1) The one he is looking at, R, is male, and L is also male

2) The one he is looking at, L, is male, and R is also male

3) The one he is looking at, R, is male, and L is female

4) The one he is looking at, L, is male, and R is female

The odds of two males becomes 50%. I don't see why this is any more or less a reasonable way to interpret the problem than the standard answer.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568990)

my original idea was to paddle in a circle with a radius of r/2 (a circle inscribed so that r of the pond is its diameter). this had the virtue of forcing the monster to run towards a spot that you were moving away from. sadly, he only has to cover 3/2 pi r in the time you take to travel 1/2 pi r, so you still lose b/c of his speed advantage. (he only needs to be 3x as fast as you to arrive at the same moment).

this made me realize that the monster's speed advantage always allows him to catch you on an arced course whenever the distance you travel is that of a circle with arc >= 1/4r

so i think you win by 1) paddling in a circle with arc < r/4, which should allow you to get to a point where he is trailing the point your bow is pointing at, and then 2) go straight to the shore

do i get to be a janitor for quants with this answer

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568833)

99 black pearls and 100 white pearls in the other

edit: I mean, assuming you have to place every pearl in a bag. Otherwise, just dump those TTT white pearls.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22568623)

only the ones that required inventing a formula are worth looking at.

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22575719)

http://en.wikipedia.org/wiki/Long_Term_Capital_Management

*destroys fund, almost collapses global economy*

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22575831)

"Think out loud and let us listen to how you estimate the cans of paint it will take to paint the Verrazano Narrows Bridge."

(http://www.autoadmit.com/thread.php?thread_id=2175711&forum_id=2#22576048)